Essential Concepts
- Given the infinite series
∞∑n=1an=a1+a2+a3+⋯
and the corresponding sequence of partial sums {Sk} where
Sk=k∑n=1an=a1+a2+a3+⋯+ak,
the series converges if and only if the sequence {Sk} converges. - The geometric series ∞∑n=1arn−1 converges if |r|<1 and diverges if |r|≥1. For |r|<1,
∞∑n=1arn−1=a1−r. - The harmonic series
∞∑n=11n=1+12+13+⋯
diverges. - A series of the form ∞∑n=1[bn−bn+1]=[b1−b2]+[b2−b3]+[b3−b4]+⋯+[bn−bn+1]+⋯
is a telescoping series. The kth partial sum of this series is given by Sk=b1−bk+1. The series will converge if and only if limk→∞bk+1 exists. In that case,
∞∑n=1[bn−bn+1]=b1−limk→∞(bk+1).
Key Equations
- Harmonic series
∞∑n=11n=1+12+13+14+⋯ - Sum of a geometric series
∞∑n=1arn−1=a1−r for |r|<1
Glossary
- convergence of a series
- a series converges if the sequence of partial sums for that series converges
- divergence of a series
- a series diverges if the sequence of partial sums for that series diverges
- geometric series
- a geometric series is a series that can be written in the form
∞∑n=1arn−1=a+ar+ar2+ar3+⋯
- harmonic series
- the harmonic series takes the form
∞∑n=11n=1+12+13+⋯
- infinite series
- an infinite series is an expression of the form
a1+a2+a3+⋯=∞∑n=1an
- partial sum
- the kth partial sum of the infinite series ∞∑n=1an is the finite sum
Sk=k∑n=1an=a1+a2+a3+⋯+ak
- telescoping series
- a telescoping series is one in which most of the terms cancel in each of the partial sums
Candela Citations
CC licensed content, Shared previously
- Calculus Volume 2. Authored by: Gilbert Strang, Edwin (Jed) Herman. Provided by: OpenStax. Located at: https://openstax.org/books/calculus-volume-2/pages/1-introduction. License: CC BY-NC-SA: Attribution-NonCommercial-ShareAlike. License Terms: Access for free at https://openstax.org/books/calculus-volume-2/pages/1-introduction